document.write( "Question 829334: Bart can peel a batch of 3000 lbs of apples in 12 hours with an old machine, while Mona can do the same job in 8 hrs using the new machine. If Bart starts peeling at 8am and Mona joins him at 9am then at what time will they finish the batch working together. So far I have 1/t1+1/t2=1/t3 so that is 1/12+1/8=1/x
\n" ); document.write( "2x+3x=24
\n" ); document.write( "6x=24
\n" ); document.write( "x=4 but I am clueless as to what I am supposed to do with the extra hour Bart has?
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Algebra.Com's Answer #499793 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Let's start from here, the correct equation for their combined rate: \"1%2F12%2B1%2F8=1%2Fx\".\r
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\n" ); document.write( "\n" ); document.write( "\"2%2F24%2B3%2F24=1%2Fx\"... but instead of solving for x, just compute the rate. That is what you really want, even if it is as a rational number, fraction form.\r
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\n" ); document.write( "\n" ); document.write( "That is \"highlight_green%285%2F24%29\" batches per hour.
\n" ); document.write( "You can also say, 5 batchs in 24 hours.\r
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\n" ); document.write( "\n" ); document.write( "Next, look at time values, not necessarily viewed on a number line. Time 8AM is time, ZERO. Let h be the time after the first hour, because Mona joins Bart after ONE hour. Bart works for 1+h hours and Mona works with him for h hours.\r
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\n" ); document.write( "\n" ); document.write( "The total jobs done will be 1.
\n" ); document.write( "This one job is \"jobByBart%2BjobByBoth=1\";
\n" ); document.write( "\"highlight_green%28highlight%28%281%2F12%29%2A1%2B%285%2F24%29%28h%2B1%29=1%29%29\"
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\n" ); document.write( "Most important is to understand the analysis, and the resulting equation. Solving it for h should be much less of a chore.
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