document.write( "Question 829334: Bart can peel a batch of 3000 lbs of apples in 12 hours with an old machine, while Mona can do the same job in 8 hrs using the new machine. If Bart starts peeling at 8am and Mona joins him at 9am then at what time will they finish the batch working together. So far I have 1/t1+1/t2=1/t3 so that is 1/12+1/8=1/x
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document.write( "2x+3x=24
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document.write( "6x=24
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document.write( "x=4 but I am clueless as to what I am supposed to do with the extra hour Bart has? \n" );
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Algebra.Com's Answer #499793 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! Let's start from here, the correct equation for their combined rate: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That is \n" ); document.write( "You can also say, 5 batchs in 24 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next, look at time values, not necessarily viewed on a number line. Time 8AM is time, ZERO. Let h be the time after the first hour, because Mona joins Bart after ONE hour. Bart works for 1+h hours and Mona works with him for h hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The total jobs done will be 1. \n" ); document.write( "This one job is \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "Most important is to understand the analysis, and the resulting equation. Solving it for h should be much less of a chore. \n" ); document.write( " |