document.write( "Question 828932: We have 500 ml of soda solution (density = 1.08 g/ml and 8% (m/m) soda).
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document.write( "We need to make a soda solution which contains 15% (m/m) soda.
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document.write( "How much of crystal soda (62.9% (m/m) water) do we need to add? \n" );
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Algebra.Com's Answer #499790 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Starter amount of soda solution is 500*1.08 grams, 540 grams of 8% m/m soda.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You want to add some x amount of 62.9% m/m WATER, which is 37.1% SODA, to the 540 grams to get 15% m/m soda. To this extent, we are no longer interested in volumes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I said this, which was WRONG------------------------------------ \n" ); document.write( " \n" ); document.write( "Solve for x, the grams of the \"Crystal Soda\" 62.9% m/m to add. \n" ); document.write( "----------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I should have said this, much more correct--------------------- \n" ); document.write( " \n" ); document.write( "Solve for x, the grams of \"Crystal Soda\", 62.9% m/m water, 37.1% SODA \n" ); document.write( "---------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "One would imagine that Crystal Soda is the name of a concentrated carbonated drink. On the other hand, 8% sodium hydroxide has a density very close to what you gave. 62.9%, concentration of the water, 37.1% m/m of SODA. \n" ); document.write( " |