document.write( "Question 70101: Please solve the following word problem:\r
\n" ); document.write( "\n" ); document.write( "Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%? \n" ); document.write( "

Algebra.Com's Answer #49976 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x= amount at 14%
\n" ); document.write( "Then 20000-x=amount at 13%\r
\n" ); document.write( "\n" ); document.write( "I=PRT where T=1 So our equation to solve:\r
\n" ); document.write( "\n" ); document.write( "0.14x+0.13(20000-x)=2720 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "0.14x+2600-0.13x=2720 subtract 2600 from both sides
\n" ); document.write( "0.01x=2720-2600
\n" ); document.write( "0.01x=120 divide both sides by 0.01
\n" ); document.write( "x=$12000 --------------------------------amount invested at 14%\r
\n" ); document.write( "\n" ); document.write( "20000-x=20000-12000=$8000----amount invested at 13%\r
\n" ); document.write( "\n" ); document.write( "Ck\r
\n" ); document.write( "\n" ); document.write( "12000(.14)+8000(.13)=2720
\n" ); document.write( "1680+1040=2720
\n" ); document.write( "2720=2720\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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