document.write( "Question 829230: Find the minimum dimensions of an open-top rectangular box that is twice as long as it is wide and can hold 12 cubic yards of material. \n" ); document.write( "
Algebra.Com's Answer #499744 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! x=length \n" ); document.write( "y=width \n" ); document.write( "z=height\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "volume, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This still has two variables. Both unknown but one of them depends on the other. This has no minimum set of dimensions. Choose any positive z and it determines the needed positive y; or choose any positive y and this determines z.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Even if you try finding derivative and looking for some extreme point, none is!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z as a function of y: \n" ); document.write( " |