document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=829034>Question 829034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following formula for n and state any restrictions: l=a+(n-1)d; first letter is an L. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499666 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=a+d(n-1)<BR>\n" );
document.write( "-d(n-1)=a-L Subtract d(n-1)+L from each side of the equation.<BR>\n" );
document.write( "d(n-1)=L-a Multiply -1 by each side of the equation.<BR>\n" );
document.write( "n-1=(L-a)/d Divide d by each side of the equation.<BR>\n" );
document.write( "n=(L-a)/d + 1 Add 1 to each side of the equation.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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