document.write( "Question 70073: convert the rectangular equation y=5x+4 to a polar equation...thanks \n" ); document.write( "
Algebra.Com's Answer #49966 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! Convert the rectangular equation y = 5x + 4 to a \r\n" ); document.write( "polar equation...thanks\r\n" ); document.write( "\r\n" ); document.write( "Since sinq = y/r, then y = r·sinq\r\n" ); document.write( "Since cosq = x/r, then x = r·cosq\r\n" ); document.write( "\r\n" ); document.write( "So substitute r·sinq for y and r·cosq for x\r\n" ); document.write( "\r\n" ); document.write( "y = 5x + 4\r\n" ); document.write( "\r\n" ); document.write( "and get\r\n" ); document.write( "\r\n" ); document.write( "r·sinq = 5r·cosq + 4\r\n" ); document.write( "\r\n" ); document.write( "Now solve for r, Get all terms that contain r on the\r\n" ); document.write( "same side of the equation:\r\n" ); document.write( "\r\n" ); document.write( "r·sinq - 5r·cosq = 4\r\n" ); document.write( "\r\n" ); document.write( "Factor out r\r\n" ); document.write( "\r\n" ); document.write( "r(sinq - 5·cosq) = 4\r\n" ); document.write( "\r\n" ); document.write( "Divide both sides by the parentheses:\r\n" ); document.write( "\r\n" ); document.write( " 4\r\n" ); document.write( "r = ----------------\r\n" ); document.write( " sinq - 5·cosq\r\n" ); document.write( " \r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |