document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828988>Question 828988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Peter Pine is doing his budget. He discovers that he has spent an average of $225.00 a month on entertainment for the year with a standard deviation of $75.00. What percent of his monthly expenses for this category would he expect to fall between $60.00 and $390.00?\r<BR>\n" );
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document.write( "The z for $60.00 = - a0.<BR>\n" );
document.write( "The percent of area associated with $60.00 = a1 %.<BR>\n" );
document.write( "The z for $390.00 = a2.<BR>\n" );
document.write( "The percent of area associated with $390.00 = a3 %.<BR>\n" );
document.write( "Adding the two percentages together, Peter calculates his answer to be a4 %. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499617 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Peter Pine is doing his budget. He discovers that he has spent an average of $225.00 a month on entertainment for the year with a standard deviation of $75.00. What percent of his monthly expenses for this category would he expect to fall between $60.00 and $390.00? <BR>\n" );
document.write( "The z for $60.00 = (60-225)/75 = -2.2<BR>\n" );
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document.write( "The percent of area between z = 0 and z = -2.2 = 0.4861<BR>\n" );
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document.write( "The z for $390.00 = 2.2<BR>\n" );
document.write( "The percent of area associated with $390.00 = +0.4861<BR>\n" );
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document.write( "Adding the two percentages together, <BR>\n" );
document.write( "Peter calculates his answer to be 2*0.4861 = 0.9722<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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