document.write( "Question 828975: i want the value of x in (x+ 1/x)^2=3 and then show by submitting the x value in the equation \n" ); document.write( "
Algebra.Com's Answer #499598 by LinnW(1048)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B+1%2Fx%29%5E2=3\"
\n" ); document.write( "take square root of each side
\n" ); document.write( "\"%28x%2B+1%2Fx%29=sqrt%283%29\"
\n" ); document.write( "multiply each side by x
\n" ); document.write( "\"%28x%5E2%2B+1%29=sqrt%283%29x\"
\n" ); document.write( "subtract sqrt(3)x from each side
\n" ); document.write( "\"x%5E2-sqrt%283%29x%2B1=0\"
\n" ); document.write( "Solutions are
\n" ); document.write( "\"x=%281%2F2%29%28sqrt%283%29-i%29\" or \"x=%281%2F2%29%28sqrt%283%29%2Bi%29\"
\n" ); document.write( "See http://www.wolframalpha.com/input/?i=x^2-sqrt%283%29x%2B1%3D0\r
\n" ); document.write( "\n" ); document.write( "below is the solution by the solver
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-1.73205080756888x%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1.73205080756888%29%5E2-4%2A1%2A1=-0.99999999999999\".
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\n" ); document.write( " The discriminant -0.99999999999999 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -0.99999999999999 is + or - \"sqrt%28+0.99999999999999%29+=+0.999999999999995\".
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\n" ); document.write( " The solution is
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1.73205080756888%2Ax%2B1+%29\"

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\n" ); document.write( "\n" ); document.write( "Plugging solutions back into the equation will take some careful work.
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