document.write( "Question 828701: The sides of a triangle all have integral measure and can be represented by the expressions x + 10, 2x -3, and 4x. For how many values of x will the sum of the two longer sides be divisible by the shortest side? \n" ); document.write( "
Algebra.Com's Answer #499538 by Edwin McCravy(20063)\"\" \"About 
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document.write( "Since the sides must be positive integers, \r\n" );
document.write( "4x will always be greater than 2x-3.\r\n" );
document.write( "So we have three cases to consider:\r\n" );
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document.write( "Case 1:  \"x%2B10+%3C=+2x-3+%3C+4x\"\r\n" );
document.write( "         \"x%2B10+%3C=+2x-3\"\r\n" );
document.write( "             \"13%3C=x\"\r\n" );
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document.write( "Since these are the sides of a triangle, the sum of the\r\n" );
document.write( "two shorter sides must by greater than the longest side\r\n" );
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document.write( "         \"x%2B10%2B2x-3%3E4x\"\r\n" );
document.write( "           \"3x%2B7%3E4x\" \r\n" );
document.write( "             \"7%3Ex\" \r\n" );
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document.write( "So there are no solutions in case 1, since those \r\n" );
document.write( "inequalities contradict each other.         \r\n" );
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document.write( "Case 2:  \"2x-3+%3C=+x%2B10+%3C=+4x\"\r\n" );
document.write( "         \"2x-3+%3C=+x%2B10\" and \"x%2B10%3C=4x\"\r\n" );
document.write( "         \"x+%3C=+13\" and \"10%3C=3x\"\r\n" );
document.write( "                    \"3%261%2F3%3C=x\"\r\n" );
document.write( "                    \"4%3C=x\"   \r\n" );
document.write( "         \r\n" );
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document.write( "Since these are the sides of a triangle, the sum of the\r\n" );
document.write( "two smaller sides must be greater than the largest side\r\n" );
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document.write( "         \"2x-3%2Bx%2B10%3E4x\"\r\n" );
document.write( "           \"3x%2B7%3E4x\" \r\n" );
document.write( "             \"7%3Ex\"\r\n" );
document.write( "             \"6%3E=x\"   \r\n" );
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document.write( "So we have the possibility \"4%3C=x%3C=6\"\r\n" );
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document.write( "For x=4  \"2x-3\",\"x%2B10\",\"4x\"\r\n" );
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document.write( "2x-3=2(4)-3=8-3=5\r\n" );
document.write( "x+10=4+10=14\r\n" );
document.write( "4x=4(4)=16\r\n" );
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document.write( "The sides are 5,14,16   \r\n" );
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document.write( "The sum of the two longer sides is 30, which \r\n" );
document.write( "is divisible by the shortest side, 5.\r\n" );
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document.write( "So one solution is x=4 \r\n" );
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document.write( "For x=5  \"2x-3\",\"x%2B10\",\"4x\"\r\n" );
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document.write( "2x-3=2(5)-3=10-3=7\r\n" );
document.write( "x+10=5+10=15\r\n" );
document.write( "4x=4(5)=20\r\n" );
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document.write( "The sides are 7,15,20\r\n" );
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document.write( "The sum of the two longer sides is 35, which \r\n" );
document.write( "is divisible by the shortest side, 7.\r\n" );
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document.write( "So a second solution is x=5 \r\n" );
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document.write( "For x=6  \"2x-3\",\"x%2B10\",\"4x\"\r\n" );
document.write( "          9,16,24\r\n" );
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document.write( "The sum of the two longer sides is 40, which \r\n" );
document.write( "is NOT divisible by the shortest side, 9. So x=6\r\n" );
document.write( "is NOT a solution.       \r\n" );
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document.write( "So from case 1, we have exactly two solutions, x=4 and x=5\r\n" );
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document.write( "Case 3:  \"2x-3+%3C+4x+%3C=+x%2B10\"\r\n" );
document.write( "         \"4x%3C=x%2B10\"\r\n" );
document.write( "         \"3x%3C=10\"\r\n" );
document.write( "        \"x%3C=3%261%2F3\"\r\n" );
document.write( "          \"x%3C=3\"   \r\n" );
document.write( "         \r\n" );
document.write( "Since these are the sides of a triangle, the sum of the\r\n" );
document.write( "two shorter sides must be greater than the longest side\r\n" );
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document.write( "         \"2x-3%2B4x%3Ex%2B10\"\r\n" );
document.write( "           \"6x-3%3Ex%2B10\" \r\n" );
document.write( "             \"5x%3E13\"\r\n" );
document.write( "               \"x%3E2%263%2F5\"\r\n" );
document.write( "             \"x%3E=3\"   \r\n" );
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document.write( "So we have one possibility x=3\r\n" );
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document.write( "\"2x-3\",\"4x\",\"x%2B10\"\r\n" );
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document.write( "2x-3=2(3)-3=6-3=3\r\n" );
document.write( "4x=4(3)=12\r\n" );
document.write( "x+10=3+10=13\r\n" );
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document.write( "The sides are 3,12,13\r\n" );
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document.write( "The sum of the two longer sides is 25, which \r\n" );
document.write( "is NOT divisible by the shortest side, 3. So x=3\r\n" );
document.write( "is NOT a solution. \r\n" );
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document.write( "------------\r\n" );
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document.write( "This exhausts all the possibilities, so the answer is \r\n" );
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document.write( "There are exactly two possibilities:\r\n" );
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document.write( "x=4 which yields sides 5, 14, 16\r\n" );
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document.write( "x=5 which yields sides 7, 15, 20 \r\n" );
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document.write( "Edwin
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