document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70091>Question 70091</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center,foci,and vertices of the ellipse and determine the lenghts of the major and minor axis.  Then sketch the graph.<BR>\n" );
document.write( "(x+2)^2/4+y^2=1  I thought both numbers in the equation needed a denominator.  I put a 1 under the y^2.  Is this correct?<BR>\n" );
document.write( "The center: (2,0)<BR>\n" );
document.write( "a^2=4   so  a=+or-2<BR>\n" );
document.write( "Vertices: (-2,0+or-2)-->(-2,2),(-2,-2)<BR>\n" );
document.write( "Major Axis: 2a=2*2=4<BR>\n" );
document.write( "Minor Axis: 2b=1<BR>\n" );
document.write( "b^2=1-->b=+or-1<BR>\n" );
document.write( "Foci: (-4,0)  (0,0)<BR>\n" );
document.write( "Is this correct?  I don't have a problem with the sketching.  I just do not understand how to do it without the denominator under y^2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49950 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the center,foci,and vertices of the ellipse and determine the lenghts of the major and minor axis. Then sketch the graph.<BR>\n" );
document.write( "(x+2)^2/4+y^2=1 <BR>\n" );
document.write( "I thought both numbers in the equation needed a denominator. I put a 1 under the y^2. Is this correct?<BR>\n" );
document.write( "COMMENT: Yes<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "The center: (-2,0)<BR>\n" );
document.write( "a^2=4 so a=2 (a is always positive)<BR>\n" );
document.write( "Vertices: (0,0) and (-4,0)<BR>\n" );
document.write( "Major Axis: 2a=2*2=4<BR>\n" );
document.write( "b^2=1 so b=1<BR>\n" );
document.write( "Minor Axis: 2b=2*1=2<BR>\n" );
document.write( "Foci: To find the foci you need to find \"c\" where c=sqrt(a^2-b^2)<BR>\n" );
document.write( "c=Sqrt(4-1)=sqrt3<BR>\n" );
document.write( "Then Foci are (-2+sqrt3,0) and (-2-sqrt3,0)<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );