document.write( "Question 828691: Liz and Mary took a canoeing trip, traveling 6 miles upstream along a river, against a 2 mph current. They returned downstream to the starting point of their trip. If the entire trip took 4 hours, what was their rate in still water ? \n" ); document.write( "
Algebra.Com's Answer #499484 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Liz and Mary took a canoeing trip, traveling 6 miles upstream along a river, against a 2 mph current. They returned downstream to the starting point of their trip. If the entire trip took 4 hours, what was their rate in still water ?
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document.write( "Let speed in still water be S
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document.write( "Traveling AGAINST the current, time taken to travel upstream = \"6%2F%28S+-+2%29\"
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document.write( "Traveling WITH the current, time taken to travel downstream = \"6%2F%28S+%2B+2%29\"
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document.write( "Since total time taken for the round trip is 4 hours, then:
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document.write( "\"6%2F%28S+-+2%29+%2B+6%2F%28S+%2B+2%29+=+4\"
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document.write( "\"6%28S+%2B+2%29+%2B+6%28S+-+2%29+=+4%28S+-+2%29%28S+%2B+2%29\" ------- Multiplying by LCD, (S - 2)(S + 2)
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document.write( "\"6S+%2B+12+%2B+6S+-+12+=+4%28S%5E2+-+4%29\"
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document.write( "\"6S+%2B+6S+=+4S%5E2+-+16\"
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document.write( "\"4S%5E2+-+12S+-+16+=+0\"
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document.write( "\"4%28S%5E2+-+3S+-+4%29+=+4%280%29\"
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document.write( "\"S%5E2+-+3S+-+4+=+0\"\r
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document.write( "Solve to obtain S, or speed of boat, in still water, ACCEPTING the POSITIVE solution, while IGNORING the 
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document.write( "negative solution.\r
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document.write( "Then do a check!! \r
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