document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828722>Question 828722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please show me how to break down and solve (x-1)(x-1)-(6x+6)(x+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499475 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First use the idea that (a+b)(c+d) = a(c+d) + b(c+d)\r<BR>\n" );
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document.write( "to go from this\r<BR>\n" );
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document.write( "(x-1)(x-1)-(6x+6)(x+1)\r<BR>\n" );
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document.write( "to this\r<BR>\n" );
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document.write( "x(x-1)-1(x-1)-[6x(x+1)+6(x+1)]\r<BR>\n" );
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document.write( "Then distribute to get\r<BR>\n" );
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document.write( "x^2-x-x+1-[6x^2+6x+6x+6]\r<BR>\n" );
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document.write( "Afterwards, distribute that negative through to get this\r<BR>\n" );
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document.write( "x^2-x-x+1-6x^2-6x-6x-6\r<BR>\n" );
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document.write( "And finally, combine like terms to get this\r<BR>\n" );
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document.write( "-5x^2-14x-5\r<BR>\n" );
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document.write( "So the final answer is <font color=\"red\">-5x^2-14x-5</font> </SPAN>\n" );
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