document.write( "Question 828691: Liz and Mary took a canoeing trip, traveling 6 miles upstream along a river, against a 2 mph current. They returned downstream to the starting point of their trip. If the entire trip took 4 hours, what was their rate in still water ? \n" ); document.write( "
Algebra.Com's Answer #499471 by josgarithmetic(39620)\"\" \"About 
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d = 6
\n" ); document.write( "r = canoe speed without current
\n" ); document.write( "c = 2, speed of current
\n" ); document.write( "T =4, total time\r
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\n" ); document.write( "\n" ); document.write( "______________speed_____________time______________distance
\n" ); document.write( "Going_________r-2_______________(___)_____________6
\n" ); document.write( "Return________r+2_______________(___)_____________6
\n" ); document.write( "Total____________________________T\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "What are the missing time parts?\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "______________speed_____________time______________distance
\n" ); document.write( "Going_________r-2_______________(6/(r-2))_____________6
\n" ); document.write( "Return________r+2_______________(6/(r+2))_____________6
\n" ); document.write( "Total____________________________T\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Obvious equation is \"6%2F%28r-2%29%2B6%2F%28r%2B2%29=T\"
\n" ); document.write( "\"6%281%2F%28r-2%29%2B1%2F%28r-2%29%29=T\"
\n" ); document.write( "\"6%28%28r%2B2%2Br-2%29%2F%28r%5E2-4%29%29=T\"
\n" ); document.write( "\"6%282r%29%2F%28r%5E2-4%29=T\"
\n" ); document.write( "\"r%2F%28r%5E2-4%29=T%2F12\"
\n" ); document.write( "\"r=%28r%5E2-4%29T%2F12\" and we already know T=4
\n" ); document.write( "\"r=%28r%5E2-4%29%284%2F12%29\"
\n" ); document.write( "\"r=%281%2F3%29%28r%5E2-4%29\"
\n" ); document.write( "\"3r=r%5E2-4\"
\n" ); document.write( "\"highlight_green%28r%5E2-3r-4=0%29\" ------ seems factorable. One solution will make sense and the other will not make sense.\r
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\n" ); document.write( "\n" ); document.write( "(r-4)(r+1)=0
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