document.write( "Question 69955: Bobby has a bond earning interest 11% yearly and another worth 3 times as much earning 10% simple inteest. If the total yearly interest is $307.50, find the value of each bond. \n" ); document.write( "
Algebra.Com's Answer #49938 by ptaylor(2198)\"\" \"About 
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Let x=value of 11% bond\r
\n" ); document.write( "\n" ); document.write( "Then 3x=value of 10% bond\r
\n" ); document.write( "\n" ); document.write( "Interest(I)=Principal(P) times Rate(R) times Time(T) or I=PRT; T=1\r
\n" ); document.write( "\n" ); document.write( "So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.11x+0.10(3x)=$307.50\r
\n" ); document.write( "\n" ); document.write( "0.11x+0.3x=307.50
\n" ); document.write( "0.41x=307.50 divide both sides by 0.41
\n" ); document.write( "x=$750-------------------------------------value of 11% bond\r
\n" ); document.write( "\n" ); document.write( "3x=3(750)=$2250-------------------------------value of 10% bond\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "750(.11)+2250(.10)=307.50\r
\n" ); document.write( "\n" ); document.write( "82.5+225=307.50
\n" ); document.write( "307.50=307.50\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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