document.write( "Question 828542: if difference between x and y is 12 and their ratio is 3:7. what is the value of y? \n" ); document.write( "

Algebra.Com's Answer #499373 by richwmiller(17219) $\"\"$ $\"About$

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x-y=12
\n" ); document.write( "x=12+y
\n" ); document.write( "x/y=3/7
\n" ); document.write( "x=3y/7
\n" ); document.write( "x=12+y
\n" ); document.write( "3y/7=12+y
\n" ); document.write( "3y=84+7y
\n" ); document.write( "-4y=84
\n" ); document.write( "y=-21
\n" ); document.write( "x=-9\r
\n" ); document.write( "\n" ); document.write( "or
\n" ); document.write( "y-x=12
\n" ); document.write( "y=12+x
\n" ); document.write( "x/y=3/7
\n" ); document.write( "y=7x/3
\n" ); document.write( "12+x=7x/3
\n" ); document.write( "36+3x=7x
\n" ); document.write( "36=4x
\n" ); document.write( "9=x
\n" ); document.write( "y=21\r
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