document.write( "Question 828533: Give AP -7,-3,1,....,state three consecutive terms in this AP which sum up to 75 \n" ); document.write( "
Algebra.Com's Answer #499367 by KMST(5328)\"\" \"About 
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In arithmetic progressions, given 3 term, the middle one is the average,
\n" ); document.write( "In other words, 3 consecutive terms add up to 3 times the middle term.
\n" ); document.write( "So, \"75%2F3=25\" is the middle term.
\n" ); document.write( "The common difference is \"1-%28-3%29=1%2B3=4\" ,
\n" ); document.write( "so the three terms are
\n" ); document.write( "\"25-4=highlight%2821%29\" ,
\n" ); document.write( "\"highlight%2825%29\" . and
\n" ); document.write( "\"25%2B4=highlight%2829%29\" .
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\n" ); document.write( "How do I know that the average of 3 terms is the middle term?
\n" ); document.write( "\"a%5Bn%5D=a%5Bn-1%5D%2Bd\" so \"a%5Bn-1%5D=a%5Bn%5D-d\" ,
\n" ); document.write( "and \"a%5Bn%2B1%5D=a%5Bn%5D%2Bd\" .
\n" ); document.write( "Adding them up you have
\n" ); document.write( "\"a%5Bn-1%5D%2Ba%5Bn%5D%2Ba%5Bn%2B1%5D=%28a%5Bn%5D-d%29%2Ba%5Bn%5D%2B%28a%5Bn%5D%2Bd%29\"
\n" ); document.write( "\"a%5Bn-1%5D%2Ba%5Bn%5D%2Ba%5Bn%2B1%5D=a%5Bn%5D-d%2Ba%5Bn%5D%2Ba%5Bn%5D%2Bd\"
\n" ); document.write( "\"a%5Bn-1%5D%2Ba%5Bn%5D%2Ba%5Bn%2B1%5D=a%5Bn%5D%2Ba%5Bn%5D%2Ba%5Bn%5D\"
\n" ); document.write( "\"a%5Bn-1%5D%2Ba%5Bn%5D%2Ba%5Bn%2B1%5D=3%2Aa%5Bn%5D\"
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