document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828439>Question 828439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Glenn leaves the city of university village in his car, driving at a speed of 65 miles per hour . Twelve minutes later , Glenn's brother Waymon leaves university village in his car, driving at a speed of 70 miles per hour. Both young men are on the same road heading to the town of New landing and drive at a constant rate. After Glenn has been driving four hours, exactly how far minutes, exactly how far in miles is Waymon ahead of Glenn ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499351 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4*65=260 miles distance Glenn traveled<BR>\n" );
document.write( "(4-12/60)*70=266<BR>\n" );
document.write( "266-260=6 miles <BR>\n" );
document.write( "Waymon would be 6 miles ahead of Glenn\r<BR>\n" );
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document.write( "another way<BR>\n" );
document.write( "In those 12 minutes, Glenn has gone 12/60*65=1/5*65=13 miles.<BR>\n" );
document.write( "Waymon gains 5 miles an hour <BR>\n" );
document.write( "5*(4-12/60)=5*3.8=19<BR>\n" );
document.write( "19-13=6 miles\r<BR>\n" );
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