document.write( "Question 828455: The question I'd like to ask is (5.3.2):
\n" ); document.write( "Solve the equation of 2cosx - 1 = 0\r
\n" ); document.write( "\n" ); document.write( "I know that I should have a set of two \"x =\" solutions, but need some help after that. I thought the answer might be \"x = (pi/3) + 2*n*pi and x = (5pi/3)+2*n*pi (where n is an integer)\", but am second guessing myself; I think it is close to that, but I might have a value or two off. If you could show me the answer, as well as how you go that answer, it would be much appreciated.
\n" ); document.write( "

Algebra.Com's Answer #499348 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
The question I'd like to ask is (5.3.2):
\n" ); document.write( "Solve the equation of 2cosx - 1 = 0\r
\n" ); document.write( "\n" ); document.write( "I know that I should have a set of two \"x =\" solutions, but need some help after that. I thought the answer might be \"x = (pi/3) + 2*n*pi and x = (5pi/3)+2*n*pi (where n is an integer)\", but am second guessing myself; I think it is close to that, but I might have a value or two off. If you could show me the answer, as well as how you go that answer, it would be much appreciated.
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\n" ); document.write( "2 cos x - 1 = 0
\n" ); document.write( "2 cos x = 1 ------ Adding 1 to both sides
\n" ); document.write( "\"cos+x+=+1%2F2\"
\n" ); document.write( "1st Quadrant: \"highlight_green%28x=+60%5Eo%29\" or \"highlight_green%28x+=+pi%2F3%29\"
\n" ); document.write( "4th Quadrant: \"highlight_green%28x=+300%5Eo%29\" or \"highlight_green%28x+=+5pi%2F3%29\"
\n" ); document.write( "You can do the check!! \r
\n" ); document.write( "\n" ); document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously.
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