document.write( "Question 828246: The ratio between the ages of X and y today is 20:1.Six years later,the ratio of their ages will be 5:1.Find the age of X today. \n" ); document.write( "
Algebra.Com's Answer #499316 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The ratio between the ages of X and y today is 20:1.
\n" ); document.write( "\"x%2Fy\" = \"20%2F1\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "x = 20y
\n" ); document.write( "Six years later, the ratio of their ages will be 5:1.
\n" ); document.write( "\"%28x%2B6%29%2F%28y%2B6%29\" = \"5%2F1\"
\n" ); document.write( "x + 6 = 5(y+6)
\n" ); document.write( "x + 6 = 5y + 30
\n" ); document.write( "x = 5y + 30 - 6
\n" ); document.write( "x = 5y + 24
\n" ); document.write( "Replace x with 20y
\n" ); document.write( "20y = 5y + 24
\n" ); document.write( "20y - 5y = 24
\n" ); document.write( "15y = 24
\n" ); document.write( "y = 24/15
\n" ); document.write( "y = 8/5
\n" ); document.write( "y = 1.6 yrs old
\n" ); document.write( "then
\n" ); document.write( "x = 20(1.6)
\n" ); document.write( "x = 32 years old\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );