document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828423>Question 828423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle is 2/3rd of a right angle and the greater of the other two exceeds to the less by 18 degree. Find the angle in degree!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499311 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3 of right angle is 2/3 of 90 or 60<BR>\n" );
document.write( "The remaining two angles total 120 since the sum of the 3 needs to be 180<BR>\n" );
document.write( "Set x = one angle<BR>\n" );
document.write( "set (x+18) = the other angle<BR>\n" );
document.write( "x + (x+18) = 120<BR>\n" );
document.write( "2x + 18 = 120<BR>\n" );
document.write( "subtract 18 from each side<BR>\n" );
document.write( " 2x = 102<BR>\n" );
document.write( " x = 51<BR>\n" );
document.write( " (x+18) = 51+18 = 69<BR>\n" );
document.write( "So the angles are 60 51 and 69 . </SPAN>\n" );
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