document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828423>Question 828423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle is 2/3rd of a right angle and the greater of the other two exceeds to the less by 18 degree. Find the angle in degree!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499310 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle is 2/3rd of a right angle and the greater of the other two exceeds to the less by 18 degree. Find the angle in degree!<BR>\n" );
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document.write( "1st: (2/3)90 = 60 degrees<BR>\n" );
document.write( "2nd: x<BR>\n" );
document.write( "3rd x + 18<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + x+18 + 60 = 180<BR>\n" );
document.write( "2x = 102<BR>\n" );
document.write( "x = 51 degrees<BR>\n" );
document.write( "x+18 = 69 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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