document.write( "Question 828379: An automobile radiator contains 10 qt of a mixture of water and antifreeze that is 20% antifreeze. How much of this mixture must be drained out and replaced with pure antifreeze in order to obtain a 50% mixture in the radiator? \n" ); document.write( "
Algebra.Com's Answer #499266 by TimothyLamb(4379)\"\" \"About 
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\n" ); document.write( "x = volume of 100% antifreeze
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\n" ); document.write( "20*10 + 100x = 50(x + 10)
\n" ); document.write( "200 + 100x = 50x + 500
\n" ); document.write( "50x = 300
\n" ); document.write( "x = 300/50
\n" ); document.write( "x = 6
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\n" ); document.write( "drain 6 quarts and replace that volume with 100% antifreeze
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