document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70050>Question 70050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1.\r<BR>\n" );
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document.write( "A)  y = 3x + 5    B)  y = – x + 5    C)  y =  x + 5    D)  y = –3x + 5\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49926 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The most important thing to note is that if you are given a line with a slope m, the slope<BR>\n" );
document.write( "of a line that is perpendicular to it is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2Fm ALIGN=MIDDLE  ALT=\"-1%2Fm\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You are given the line y = -3x + 1.  This is in the form of the slope-intercept equation which<BR>\n" );
document.write( "is the form y = mx + b.  In this slope-intercept equation m is the slope.  By comparing the given equation to<BR>\n" );
document.write( "the slope-intercept form you can see that the slope m in the given equation is -3.  Therefore,<BR>\n" );
document.write( "a line perpendicular to the graph of the given equation is the negative inverse of -3.  The <BR>\n" );
document.write( "slope of the perpendicular line, therefore, is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F-3+=+%2B1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F-3+=+%2B1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Therefore, the line perpendicular to the graph of y = -3x + 1 has the slope <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "In slope intercept form you can begin to write the equation of this perpendicular:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%281%2F3%29x+%2B+b ALIGN=MIDDLE  ALT=\"y+=+%281%2F3%29x+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The one thing we know about this line is that it goes through the point (0,5).  So if you<BR>\n" );
document.write( "go to the above, <BR>\n" );
document.write( "beginning of our perpendicular equation and substitute 0 for x and 5 for y the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+=+%281%2F3%29%2A0+%2B+b ALIGN=MIDDLE  ALT=\"5+=+%281%2F3%29%2A0+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "This reduces to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+=+b ALIGN=MIDDLE  ALT=\"5+=+b\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Substitute 5 for b in the equation for the perpendicular line.  With this substitution<BR>\n" );
document.write( "the equation becomes:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%281%2F3%29x+%2B+5 ALIGN=MIDDLE  ALT=\"y+=+%281%2F3%29x+%2B+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Trust me, this is correct.  However, it does not match any of the answers listed.  Somebody<BR>\n" );
document.write( "made a mistake.  If you have doubts, graph the given equation and the above equation<BR>\n" );
document.write( "for the perpendicular line and you will see they are perpendicular, and the perpendicular<BR>\n" );
document.write( "line goes through (0,5).\r<BR>\n" );
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