document.write( "Question 828291: At 1 pm, ship a leaves port heading due west at x miles per hour. two hours later ship B is 100 miles due south of the same port and heading due north at y miles per hour. at 5 pm how far apart are the ship.
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Algebra.Com's Answer #499219 by richwmiller(17219) $\"\"$ $\"About$

You can put this solution on YOUR website!
we are dealing with right triangles here.
\n" ); document.write( "we don't have real number speeds just x and y.
\n" ); document.write( "4x is the distance traveled west by ship a
\n" ); document.write( "3y-100 is the distance traveled north by ship b
\n" ); document.write( "the distance between them is the hypotenuse
\n" ); document.write( "(4x)^2+(3y-100)^2=d^2
\n" ); document.write( "16 x^2+9 y^2-600 y+10000 = d^2\r
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