document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828283>Question 828283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The roof of a lean-to-garden shed has a gradient of 0.35.find the height....they have given the base as 1.5m and a shorter height 1.8m its like a house  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499200 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The roof of a lean-to-garden shed has a gradient of 0.35.find the height....they have given the base as 1.5m and a shorter height 1.8m its like a house <BR>\n" );
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document.write( "It sounds like you have a right triangle with base = 1.5, <BR>\n" );
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document.write( "Use a proportion to get:<BR>\n" );
document.write( "(height of that triangle)/1.5 = 35/100<BR>\n" );
document.write( "height of that triangle = 1.5*0.35 = 0.5250<BR>\n" );
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document.write( "Ans: greater height of the lean-to = 1.8 + 0.5250 = 2.325 meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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