document.write( "Question 828281: log 3x = log 5 + log (x - 2)\r
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document.write( "I think I am getting this. But when I follow the equation, my answer is just off, not sure where I'm going wrong now. Can some one please help, show me the error of my ways.\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #499195 by Edwin McCravy(20063) You can put this solution on YOUR website! \r\n" ); document.write( "log(3x) = log(5) + log(x-2)\r\n" ); document.write( "\r\n" ); document.write( "Use this rule on the right:\r\n" ); document.write( "\r\n" ); document.write( "Taking out log of an addition changes the\r\n" ); document.write( "addition to multiplication:\r\n" ); document.write( "\r\n" ); document.write( "log(3x) = log[5(x-2)]\r\n" ); document.write( "\r\n" ); document.write( "log(3x) = log[5x-10]\r\n" ); document.write( "\r\n" ); document.write( "Use the rule: if log(A)=log(B) then A=B\r\n" ); document.write( "\r\n" ); document.write( " 3x = 5x-10\r\n" ); document.write( " \r\n" ); document.write( " -2x = -10\r\n" ); document.write( "\r\n" ); document.write( " x = 5\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |