document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828272>Question 828272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help Please\r<BR>\n" );
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document.write( "In the Smoky Mountains of Tennessee, the percent of moisture that falls as snow rather than rain is approximated by P%=10.0 ln h-80,where P is the percent of snow moisture at an altitude h feet. What altitude corresponds to 5 percent snow moisture? Round to the nearest hundred feet.\r<BR>\n" );
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document.write( "I need help.  I am so confused. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499186 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the percent of moisture that falls as snow rather than rain is approximated by P%=10.0 ln h-80,where P is the percent of snow moisture at an altitude h feet. What altitude corresponds to 5 percent snow moisture? Round to the nearest hundred feet. <BR>\n" );
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document.write( "P% = 10*ln(h-80)<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "5 = 10*ln(h-80)<BR>\n" );
document.write( "ln(h-80) = 1/2<BR>\n" );
document.write( "h-80 = e^(1/2) = 1.65<BR>\n" );
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document.write( "height = 81.65 ft<BR>\n" );
document.write( "height = 100 ft when rounded to the nearest hundred<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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