document.write( "Question 828226: One number is three more than a second number. Forty-nine more than the product of the two numbers is 89. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #499171 by Seutip(231) $\"\"$ $\"About$

You can put this solution on YOUR website!
Hello do the breathing first, inhale exhale. :)\r
\n" ); document.write( "\n" ); document.write( "Let x+3 - be first number
\n" ); document.write( " x - be second number\r
\n" ); document.write( "\n" ); document.write( "Then interpret,\r
\n" ); document.write( "\n" ); document.write( " $\"49+%2B+%28x%2B3%29%28x%29=89\"$
\n" ); document.write( " $\"49%2Bx%5E2%2B3x=89\"$
\n" ); document.write( " $\"x%5E2%2B3x-40=0\"$
\n" ); document.write( " $\"%28x-5%29%28x%2B8%29\"$ \r
\n" ); document.write( "\n" ); document.write( "So it's either,
\n" ); document.write( "x-5=0
\n" ); document.write( "x=5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "or,\r
\n" ); document.write( "\n" ); document.write( "x+8=0
\n" ); document.write( "x=-8\r
\n" ); document.write( "\n" ); document.write( "Try substituting :)
\n" ); document.write( " If x=5
\n" ); document.write( "x+5 = 8
\n" ); document.write( "x = 5\r
\n" ); document.write( "\n" ); document.write( "If x=-8
\n" ); document.write( "x+5 = -3
\n" ); document.write( "x=-8\r
\n" ); document.write( "\n" ); document.write( "49 + (8)(3)=89
\n" ); document.write( "49 + (-8)(-3)=89\r
\n" ); document.write( "\n" ); document.write( "HOPE hat helps :) \n" ); document.write( "

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