document.write( "Question 828236: Find the equation of the line parallel to the line x-3y=2 and passing at a distance 2√10 from the given line. \n" ); document.write( "
Algebra.Com's Answer #499167 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+x+-+3y+=+2+\"
\n" ); document.write( "\"+3y+=+x+-+2+\"
\n" ); document.write( "\"+y+=+%281%2F3%29%2Ax+-+2%2F3+\"
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\n" ); document.write( "The slope of the line I want will
\n" ); document.write( "have a slope \"+m+=+1%2F3+\" also
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\n" ); document.write( "I need a point that this line will go through
\n" ); document.write( "to get the equation
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\n" ); document.write( "Setting \"+y=0+\",
\n" ); document.write( "\"+x+-+3%2A0+=+2+\"
\n" ); document.write( "\"+x+=+2+\"
\n" ); document.write( "So, the given line passes through (2,0)
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\n" ); document.write( "The line through this point and perpendicular
\n" ); document.write( "to the given line will have slope = \"+-1%2Fm+=+-3+\"
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\n" ); document.write( "\"+%28+y-0+%29+%2F+%28+x-2+%29+=+-3+\"
\n" ); document.write( "\"+y+=+-3%2A%28+x-2+%29+\"
\n" ); document.write( "(1) \"+y+=+-3x+%2B+6+\"
\n" ); document.write( "-------------------
\n" ); document.write( "Now I need to find the point on this line that is
\n" ); document.write( "\"+d+=+2%2Asqrt%2810%29+\" distance from (2,0)
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\n" ); document.write( "\"+%28+2%2Asqrt%2810%29+%29%5E2+=+%28+y-0+%29%5E2+%2B+%28+x-2+%29%5E2+\"
\n" ); document.write( "\"+40+=+y%5E2+%2B+%28x-2%29%5E2+\"
\n" ); document.write( "Substituting from (1) above:
\n" ); document.write( "\"+40+=+%28-3x%2B6%29%5E2+%2B+%28x-2%29%5E2+\"
\n" ); document.write( "\"+40+=+9x%5E2+-36x+%2B+36+%2B+x%5E2+-+4x+%2B+4+\"
\n" ); document.write( "\"+10x%5E2+-+40x+=+0+\"
\n" ); document.write( "\"+x%5E2+-+4x+=+0+\"
\n" ); document.write( "\"+x%2A%28+x-4%29+=+0+\"
\n" ); document.write( "\"+x+=+4+\"
\n" ); document.write( "------------------
\n" ); document.write( "Plugging this into (1),
\n" ); document.write( "(1) \"+y+=+-3%2A4+%2B+6+\"
\n" ); document.write( "(1) \"+y+=+-12+%2B+6+\"
\n" ); document.write( "(1) \"+y+=+-6+\"
\n" ); document.write( "----------------------
\n" ); document.write( "Now I have \"+m+=+1%2F3+\"
\n" ); document.write( "and the point ( 4,-6)
\n" ); document.write( "Using the point-slope formula:
\n" ); document.write( "\"+%28y-%28-6%29+%29+%2F+%28+x-4%29+=+1%2F3+\"
\n" ); document.write( "\"+%28+y%2B6+%29+%2F+%28+x-4+%29+=+1%2F3+\"
\n" ); document.write( "\"+y+%2B+6+=+%281%2F3%29%2A%28x-4%29+\"
\n" ); document.write( "\"+y+%2B+6+=+%281%2F3%29%2Ax+-+4%2F3+\"
\n" ); document.write( "\"+y+=+%281%2F3%29%2Ax+-+18%2F3+-+4%2F3+\"
\n" ); document.write( "\"+y+=+%281%2F3%29%2Ax+-22%2F3+\" answer
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\n" ); document.write( "Here's plots of the 3 lines:
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