document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828186>Question 828186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a mixture of concrete, there are 4 lbs of cement mix. If the mixture contains a total of 250 lbs of these two ingredients, how many pounds of gravel are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499125 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499125\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Is this concrete supposed to be composed of just cement and gravel, and no other dry matter?  If so, go this way:\r<BR>\n" );
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document.write( "g = pounds of gravel.<BR>\n" );
document.write( "4 pounds cement-mix plus g pounds of gravel equals 250 pounds concrete mixture.<BR>\n" );
document.write( "4+g=250<BR>\n" );
document.write( "g=250-4 </SPAN>\n" );
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