document.write( "Question 68811: Solve for x. I did the following.
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document.write( "20 (2)=5*x-2
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document.write( "40=5x(-2)
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document.write( "40=-10
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document.write( "x=4
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document.write( "I believe I did it wrong but I am not for sure. Thank you in advance. \n" );
document.write( "
Algebra.Com's Answer #49912 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! I take a little different interpretation of your problem, assuming that there were NO PARENTHESES around the x-2! I think the solution by the other tutor is wrong!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20(2) = 5*x -2 \n" ); document.write( "40 = 5x-2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add +2 to each side: \n" ); document.write( "42 = 5x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 5: \n" ); document.write( "x= 42/5 or 8.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |