document.write( "Question 828141: The average length of stay in a chronic disease hospital for a certain type of patient is 60 days with a standard deviation of 15. Suppose it is reasonable to assume an approximately normal distribution of lengths of stay.
\n" ); document.write( "a. what percentage of patients stay less than 50 days? \r
\n" ); document.write( "\n" ); document.write( "I don't even know how to start. I know that 60 is the mean and obviously the standard deviation is 15 but I don't know what to do with this data.
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Algebra.Com's Answer #499079 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The average length of stay in a chronic disease hospital for a certain type of patient is 60 days with a standard deviation of 15. Suppose it is reasonable to assume an approximately normal distribution of lengths of stay.
\n" ); document.write( "a. what percentage of patients stay less than 50 days?
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\n" ); document.write( "z(50) = (50-60)/15 = -10/15 = -2/3
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\n" ); document.write( "P(x < 50) = P(z < -2/3) = 0.2525 = 25.25%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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