document.write( "Question 828121: Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third \n" ); document.write( "

Algebra.Com's Answer #499039 by Fombitz(32388) $\"\"$ $\"About$

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First integer : $\"N\"$
\n" ); document.write( "Next two consecutive integers : $\"N%2B1\"$ , $\"N%2B2\"$
\n" ); document.write( "The sum of first and twice the second : $\"N+%2B+2%2A%28N%2B1%29\"$
\n" ); document.write( "is means \"equals\"
\n" ); document.write( "80 minus three times the third : $\"80-3%2A%28N%2B2%29\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"N%2B+2%2A%28N%2B1%29=80-3%2A%28N%2B2%29\"$
\n" ); document.write( " $\"N%2B2N%2B2=80-3N-6\"$
\n" ); document.write( "I leave you that to solve for $\"N\"$ .
\n" ); document.write( "Re-post if you still need help. \n" ); document.write( "

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