document.write( "Question 827885: Suppose y=x/u, where u is a function of x. Show that y(du/dx)+ u(dy/dx)=1 \r
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Algebra.Com's Answer #498975 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! The easiest way to do this is to use implicit differentiation. (I will do with without implicit differentiation later.) \n" ); document.write( "If we multiply each side of the equation by u we get: \n" ); document.write( "y*u = x \n" ); document.write( "Implicitly differentiate. On the left side we will use the product rule: \n" ); document.write( "y*(du/dx) + u*(dy/dx) = 1 \n" ); document.write( "And we're done! \n" ); document.write( "Using \"regular\" differentiation (the quotient rule) on y = x/u, we get: \n" ); document.write( " \n" ); document.write( "Now we use some algebra to transform this equation into the desired one. Since the desired equation has two terms on one side, I will split the fraction (i.e. \"un-subtract\"): \n" ); document.write( " \n" ); document.write( "which simplifies to: \n" ); document.write( " \n" ); document.write( "Factoring the second fraction: \n" ); document.write( " \n" ); document.write( "Since y = x/u we can substitute in for the x/u: \n" ); document.write( " \n" ); document.write( "Multiplying both sides by u (to eliminate the fractions): \n" ); document.write( " \n" ); document.write( "Adding y*(du/dx) to both sides: \n" ); document.write( " \n" ); document.write( "And we're done! \n" ); document.write( " |