document.write( "Question 828010: Solve using quadratic formula.
\n" ); document.write( "The diagonal of a rectangle is 15m long and one side is 2m longer than the other. Find the dimensions of the rectangle.
\n" ); document.write( "Please HELP
\n" ); document.write( "

Algebra.Com's Answer #498971 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
The diagonal of a rectangle is 15m long and one side is 2m longer than the other.
\n" ); document.write( ".
\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w+2 = length
\n" ); document.write( ".
\n" ); document.write( "applying Pythagorean's theorem:
\n" ); document.write( "w^2 + (w+2)^2 = 15
\n" ); document.write( "w^2 + (w+2)(w+2) = 15
\n" ); document.write( "w^2 + w^2+4w+4 = 15
\n" ); document.write( "2w^2+4w+4 = 15
\n" ); document.write( "2w^2+4w-11 = 0
\n" ); document.write( "applying the quadratic formula we get:
\n" ); document.write( "w = 1.55 m (width)
\n" ); document.write( ".
\n" ); document.write( "Length:
\n" ); document.write( "w+2 = 1.55+2 = 3.55 m (length)
\n" ); document.write( ".
\n" ); document.write( "Dimensions are:
\n" ); document.write( "1.55m by 3.55 m
\n" ); document.write( ".
\n" ); document.write( "Details of quadratic formula:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"2w%5E2%2B4w%2B-11+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%284%29%5E2-4%2A2%2A-11=104\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=104 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-4%2B-sqrt%28+104+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"w%5B1%5D+=+%28-%284%29%2Bsqrt%28+104+%29%29%2F2%5C2+=+1.54950975679639\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%284%29-sqrt%28+104+%29%29%2F2%5C2+=+-3.54950975679639\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"2w%5E2%2B4w%2B-11\" can be factored:
\n" ); document.write( " \"2w%5E2%2B4w%2B-11+=+2%28w-1.54950975679639%29%2A%28w--3.54950975679639%29\"
\n" ); document.write( " Again, the answer is: 1.54950975679639, -3.54950975679639.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B4%2Ax%2B-11+%29\"

\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );