document.write( "Question 827668: A tree on top of a hill casts a shadow of 20 m long down the hill. Of the angle of elevation of the sun is 75 degrees and the hill is inclined 45 degrees, find the height of the tree \n" ); document.write( "
Algebra.Com's Answer #498967 by KMST(5328)\"\" \"About 
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RS = 20 m = shadow of tree
\n" ); document.write( "Consider right triangle RSP.
\n" ); document.write( "\"PS=RS%2Acos%2845%5Eo%29=%2820m%29%28sqrt%282%29%2F2%29=14.14m\" (rounded to nearest 0.1m)
\n" ); document.write( "\"RP=RS%2Asin%2845%5Eo%29=%2820m%29%28sqrt%282%29%2F2%29=14.14m\" (rounded to nearest 0.1m)
\n" ); document.write( "Consider right triangle TSP.
\n" ); document.write( "\"PT=PS%2Atan%2875%5Eo%29=%2814.14m%29%2A3.732=52.78m\" (rounded to nearest 0.1m)
\n" ); document.write( "The height of the tree is
\n" ); document.write( "\"RT=PT-RP=52.78m-14.14m=38.64m\" (rounded to nearest 0.1m).
\n" ); document.write( "(Maybe it should be rounded to 39 meters, since the shadow's length and angles do not seem to have been measured with such fine precision).
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