document.write( "Question 69860: The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet, then what are the length and width?
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document.write( "How do I solve this? \n" );
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Algebra.Com's Answer #49895 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation for each statement/phrase: \n" ); document.write( ": \n" ); document.write( "\"length of a rectangular lot is 50 feet more than the width.\" \n" ); document.write( " L = W + 50 \n" ); document.write( ": \n" ); document.write( "I assume you know the perimeter equation: \n" ); document.write( "\"If the perimeter is 500 feet,\" \n" ); document.write( " 2L + 2W = 500 \n" ); document.write( ": \n" ); document.write( "then what are the length and width? \n" ); document.write( ": \n" ); document.write( "If we could get the above equation to be a single unknown it would be easy to \n" ); document.write( "solve. The 1st equation says that L = (W+50), substitute (W+50) for L in the \n" ); document.write( "perimeter equation: \n" ); document.write( "2(W+50) + 2W = 500 \n" ); document.write( ": \n" ); document.write( "We can simplify this equation by dividing thru by 2, then we have: \n" ); document.write( "(W+50) + W = 250; a very simple equation to solve for W \n" ); document.write( ": \n" ); document.write( "2W = 250 - 50 \n" ); document.write( "2W = 200 \n" ); document.write( "W = 200/2 \n" ); document.write( "W = 100 ft is the width; \n" ); document.write( ": \n" ); document.write( "Remember: \"length of a rectangular lot is 50 feet more than the width.\" \n" ); document.write( "L = 100 + 50 \n" ); document.write( "L = 150 \n" ); document.write( ": \n" ); document.write( "Check our solutions in the perimeter equation: \n" ); document.write( "2(150) + 2(100) = 500 \n" ); document.write( "; \n" ); document.write( "How about this? Comprendez? \n" ); document.write( " |