document.write( "Question 70052: Can someone please show me the step by step process in solving this type of problem? Thanks a bunch. \r
\n" ); document.write( "\n" ); document.write( "Terri Hoelker invested some money at 3.5% simple interest, and $5000 more than 3 times this amount at 4%. She earned $1440 in interest. How much did she invest at each rate?
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Algebra.Com's Answer #49894 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I AM ASSUMING THAT SHE INVESTED HER MONEY FOR 1 YEAR\r
\n" ); document.write( "\n" ); document.write( "Let x= amount invested at 3.5%
\n" ); document.write( "Then 3x+$5000=amount invested at 4%\r
\n" ); document.write( "\n" ); document.write( "INTEREST(I)=PRINCIPAL (P) TIMES RATE(R) TIMES TIME(T) or I=PRT
\n" ); document.write( "So our equation to solve is:
\n" ); document.write( "0.035x+0.04(3x+5000)=1440 get rid of parens
\n" ); document.write( "0.035x+0.12x+200=1440 subtract 200 from both sides
\n" ); document.write( "0.155x=1440-200
\n" ); document.write( "0.155x=1240 divide both sides by 0.155
\n" ); document.write( "x=$8000--------------------------amount invested at 3.5%
\n" ); document.write( "3x+5000=24000+5000=29000----------------------amount invested at 4%\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.035(8000)+0.04(29000)=1440
\n" ); document.write( "280+1160=1440
\n" ); document.write( "1440=1440\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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