document.write( "Question 827926: Please help me solve this equation. Find the quotient of (2-3i) (1+i) \n" ); document.write( "
Algebra.Com's Answer #498936 by MathLover1(20850)\"\" \"About 
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the quotient of \"%282-3i%29\" and \"+%281%2Bi%29+\": \"%282-3i%29%2F%281%2Bi%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+%282-3i%29%2F%281%2Bi%29+\" ...........both numerator and denominator multiply by \"+%281-i%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282-3i%29%281-i%29%29%2F%28%281%2Bi%29%281-i%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282-3i%29%281-i%29%29%2F%281%5E2-i%5E2%29+\" ...since \"i=sqrt%28-1%29\"=> \"i%5E2=%28sqrt%28-1%29%29%5E2=-1\", so we have\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282-3i%29%281-i%29%29%2F%281-%28-1%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282-3i%29%281-i%29%29%2F%281%2B1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282-3i%29%281-i%29%29%2F2+\" ..................now do numerator\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282%2A1-3i%2A1%2B2%28-i%29-3i%28-I%29%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282-3i-2i%2B3i%5E2%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282-5i%2B3%28-1%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282-5i-3%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-1-5i%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"-1%2F2-5i%2F2+\"\r
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