document.write( "Question 827911: Why is this 20? I keep getting -20.
\n" ); document.write( "(x+5/5)-(2x-12/7)=1
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Algebra.Com's Answer #498930 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"+%28x%2B5%29%2F5-%282x-12%29%2F7=1+\" ............both sides multiply by \"35\" which is divisible with both \"5\" and \"7\"\r
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\n" ); document.write( "\n" ); document.write( "\"35%28x%2B5%29%2F5-35%282x-12%29%2F7=1%2A35\"\r
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\n" ); document.write( "\n" ); document.write( "\"cross%2835%297%28x%2B5%29%2Fcross%285%29-cross%2835%295%282x-12%29%2Fcross%287%29=35\"\r
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\n" ); document.write( "\n" ); document.write( "\"7%28x%2B5%29-5%282x-12%29=35\"\r
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\n" ); document.write( "\n" ); document.write( "\"7x%2B35-10x%2B60=35\".............you probably made mistake here when multiply \"-5\" and \"-12\"\r
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\n" ); document.write( "\n" ); document.write( "\"-3x%2B95=35\"\r
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\n" ); document.write( "\n" ); document.write( "\"95-35=3x\"\r
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\n" ); document.write( "\n" ); document.write( "\"60=3x\"\r
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\n" ); document.write( "\n" ); document.write( "\"60%2F3=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"20=x\"\r
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