document.write( "Question 69956: x^2-5x-14=0 \n" ); document.write( "
Algebra.Com's Answer #49887 by gsmani_iyer(201)\"\" \"About 
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\n" ); document.write( " \"x%5E2-5x-14+=+0\"
\n" ); document.write( " = \"x%5E2%2B2x-7x-14+=+0\" = \"x%28x%2B2%29-7%28x%2B2%29=0\" = \"%28x%2B2%29%28x-7%29=0\"
\n" ); document.write( "So, either (x+2) or (x-7) = 0. If (x+2) = 0, then x = -2. If (x-7) = 0,
\n" ); document.write( "then x = 7.
\n" ); document.write( "x = {-2, 7}. Answer.
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\n" ); document.write( "gsm
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