document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=827795>Question 827795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of a line perpendicular to the given line but passing through the given point.<BR>\n" );
document.write( "y=-x+3;(-2,-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498863 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope a perpendicular line is the negative reciprocal of -1 which is 1.<BR>\n" );
document.write( "Use y=mx+b as a template. m=1. for the point(-2,-2), x=-2,y=-2<BR>\n" );
document.write( "-2=(1)(-2)+b<BR>\n" );
document.write( "-2=-2+b<BR>\n" );
document.write( "ads 2 to each side<BR>\n" );
document.write( "0 = b<BR>\n" );
document.write( "So our equation is y = (1)x + 0 <BR>\n" );
document.write( "or y=x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );