document.write( "Question 70003: convert the following equation to Cartesian coordinates,
\n" ); document.write( "r sin 0=-2 \n" ); document.write( "
Algebra.Com's Answer #49880 by venugopalramana(3286)\"\" \"About 
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convert the following equation to Cartesian coordinates,
\n" ); document.write( "r sin 0=-2
\n" ); document.write( "HOPE YOU MEAN RSIN(THETA)=-2...LET US USE T FOR THETA...
\n" ); document.write( "RSIN(T)=-2
\n" ); document.write( "HOPE YOU KNOW THESE 2 EQNS..
\n" ); document.write( "RCOS(T)=X
\n" ); document.write( "RSIN(T)=Y
\n" ); document.write( "HENCE Y=-2 IS THE CARTESIAN FORM\r
\n" ); document.write( "\n" ); document.write( "ALITER...IF YOU KNOW THE OTHER FORMULAE...
\n" ); document.write( "R = SQRT(X^2+Y^2)
\n" ); document.write( "TAN(T)=Y/X
\n" ); document.write( "SIN(T)/COS(T)=Y/X
\n" ); document.write( "SIN(T)=(Y/X)COS(T)=(Y/X)/SEC(T)=(Y/X)/[SQRT(1+TAN^2(T)]
\n" ); document.write( "= (Y/X)/SQRT[1+Y^2/X^2]=(Y/X)/[SQRT(X^2+Y^2)/X]
\n" ); document.write( "=Y/SQRT(X^2+Y^2)
\n" ); document.write( "HENCE THE GIVEN EQN. IN CARTESIAN COORDINATES IS
\n" ); document.write( "SQRT(X^2+Y^2)*Y/SQRT(X^2+Y^2)=Y = -2
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