document.write( "Question 827594: two cyclist were 190 km apart left in 7:00 am. They travelled each other with rates of 32 and 44 kph. what time did they meet? \n" ); document.write( "
Algebra.Com's Answer #498774 by mananth(16946) You can put this solution on YOUR website! let one travel x miles to meet \n" ); document.write( "the other travels 109-x miles\r \n" ); document.write( "\n" ); document.write( "the time they take is the same since they leave at the same time\r \n" ); document.write( "\n" ); document.write( "x/32= (109-x)/44\r \n" ); document.write( "\n" ); document.write( "44*x=32*(109-x)\r \n" ); document.write( "\n" ); document.write( "44x= 32*109-32x\r \n" ); document.write( "\n" ); document.write( "76x= 32*109\r \n" ); document.write( "\n" ); document.write( "76x= 109*32\r \n" ); document.write( "\n" ); document.write( "x= 109*32/76\r \n" ); document.write( "\n" ); document.write( "x=45.9\r \n" ); document.write( "\n" ); document.write( "t= d/r\r \n" ); document.write( "\n" ); document.write( "=45.9/32 \n" ); document.write( "they meet after 1.43 hours\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |