document.write( "Question 827594: two cyclist were 190 km apart left in 7:00 am. They travelled each other with rates of 32 and 44 kph. what time did they meet? \n" ); document.write( "
Algebra.Com's Answer #498774 by mananth(16946)\"\" \"About 
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let one travel x miles to meet
\n" ); document.write( "the other travels 109-x miles\r
\n" ); document.write( "\n" ); document.write( "the time they take is the same since they leave at the same time\r
\n" ); document.write( "\n" ); document.write( "x/32= (109-x)/44\r
\n" ); document.write( "\n" ); document.write( "44*x=32*(109-x)\r
\n" ); document.write( "\n" ); document.write( "44x= 32*109-32x\r
\n" ); document.write( "\n" ); document.write( "76x= 32*109\r
\n" ); document.write( "\n" ); document.write( "76x= 109*32\r
\n" ); document.write( "\n" ); document.write( "x= 109*32/76\r
\n" ); document.write( "\n" ); document.write( "x=45.9\r
\n" ); document.write( "\n" ); document.write( "t= d/r\r
\n" ); document.write( "\n" ); document.write( "=45.9/32
\n" ); document.write( "they meet after 1.43 hours\r
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