document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=827593>Question 827593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the solution in this problem?The ratio between the base and the altitude is 2:3.If the area of the triangle is 108 sq. cm.,what is the base? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498773 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the common multiple be x\r<BR>\n" );
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document.write( "height = 2x<BR>\n" );
document.write( "base = 3x\r<BR>\n" );
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document.write( "Area = 1/2 * base * height\r<BR>\n" );
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document.write( "108= 1/2 * 2x * 3x\r<BR>\n" );
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document.write( "3x^2=108\r<BR>\n" );
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document.write( "x^2=36 <BR>\n" );
document.write( "x= +6\r<BR>\n" );
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document.write( "height = 2x= 12<BR>\n" );
document.write( "base = 3x= 18 </SPAN>\n" );
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