document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=827595>Question 827595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This my system of linear equation problem.\r<BR>\n" );
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document.write( "3x+2y = -1  <BR>\n" );
document.write( "5x+4y = 0\r<BR>\n" );
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document.write( "I get this step right.<BR>\n" );
document.write( "Expressing x as a function of y (from the first equation) x = (-1 -2y)/3\r<BR>\n" );
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document.write( "How do I get my answer from this cause this is where Im getting confused<BR>\n" );
document.write( "5(-1+2y)/3+4y = 0  \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498772 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try Elimination Method.\r<BR>\n" );
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document.write( "Multiply the first equation by 2, and then subtract one equation from the other equation. </SPAN>\n" );
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