document.write( "Question 827595: This my system of linear equation problem.\r
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document.write( "3x+2y = -1
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document.write( "5x+4y = 0\r
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document.write( "I get this step right.
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document.write( "Expressing x as a function of y (from the first equation) x = (-1 -2y)/3\r
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document.write( "How do I get my answer from this cause this is where Im getting confused
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document.write( "5(-1+2y)/3+4y = 0 \r
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Algebra.Com's Answer #498771 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 3x+2y = -1 \n" ); document.write( "5x+4y = 0\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply equation by 3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-5-10y+12y=0\r \n" ); document.write( "\n" ); document.write( "2y=5 \n" ); document.write( "y=5/2\r \n" ); document.write( "\n" ); document.write( "plug y in any equation above you get x=-2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |