document.write( "Question 70028: 1. A parking lot has a perimeter of 600 ft. the width is 30 ft less than the length. find the dimensions of the parking lot.\r
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document.write( "2. Solve and write in interval notation for the solution set
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document.write( " -5 <_ 2x + 1 < 7 \n" );
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Algebra.Com's Answer #49872 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! 1. Use the formula for a perimeter: \n" ); document.write( "Perimeter = 2(Length + Width) \n" ); document.write( "P=2(L+w) \n" ); document.write( "P=600 \n" ); document.write( "L=L \n" ); document.write( "w=L-30 \n" ); document.write( ". \n" ); document.write( "P=2(L+w) \n" ); document.write( "600=(2(L+(L-30)) [plug-in the values] \n" ); document.write( "600=2(2L-30) [simplify] \n" ); document.write( "600/2=2(2L -30)/2 \n" ); document.write( "300=2L-30 \n" ); document.write( "300+30=2L-30+30 \n" ); document.write( "330=2L \n" ); document.write( "330/2=2L/2 \n" ); document.write( "165=L \n" ); document.write( ". \n" ); document.write( "Since the Width = Length -30, \n" ); document.write( "Than, Width = 165-30=135 \n" ); document.write( ". \n" ); document.write( "Check by plugging-in all of the values back into the original formula: \n" ); document.write( "P=2(L+w) \n" ); document.write( "600=2(165+135) \n" ); document.write( "600=2(300) \n" ); document.write( "600=600 [checks out] \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "2. Solve and write in interval notation for the solution set \n" ); document.write( "-5 <_ 2x + 1 < 7[isolate the x variable] \n" ); document.write( "-5-1 <_ 2x + 1-1 < 7-1 \n" ); document.write( "-6 <_ 2x < 6 \n" ); document.write( "-6/2 <_ 2x/2 < 6/2 \n" ); document.write( "-3 <_ x < 3 \n" ); document.write( ". \n" ); document.write( "[-3, 3)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |