document.write( "Question 70028: 1. A parking lot has a perimeter of 600 ft. the width is 30 ft less than the length. find the dimensions of the parking lot.\r
\n" ); document.write( "\n" ); document.write( "2. Solve and write in interval notation for the solution set
\n" ); document.write( " -5 <_ 2x + 1 < 7
\n" ); document.write( "

Algebra.Com's Answer #49872 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
1. Use the formula for a perimeter:
\n" ); document.write( "Perimeter = 2(Length + Width)
\n" ); document.write( "P=2(L+w)
\n" ); document.write( "P=600
\n" ); document.write( "L=L
\n" ); document.write( "w=L-30
\n" ); document.write( ".
\n" ); document.write( "P=2(L+w)
\n" ); document.write( "600=(2(L+(L-30)) [plug-in the values]
\n" ); document.write( "600=2(2L-30) [simplify]
\n" ); document.write( "600/2=2(2L -30)/2
\n" ); document.write( "300=2L-30
\n" ); document.write( "300+30=2L-30+30
\n" ); document.write( "330=2L
\n" ); document.write( "330/2=2L/2
\n" ); document.write( "165=L
\n" ); document.write( ".
\n" ); document.write( "Since the Width = Length -30,
\n" ); document.write( "Than, Width = 165-30=135
\n" ); document.write( ".
\n" ); document.write( "Check by plugging-in all of the values back into the original formula:
\n" ); document.write( "P=2(L+w)
\n" ); document.write( "600=2(165+135)
\n" ); document.write( "600=2(300)
\n" ); document.write( "600=600 [checks out]
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "2. Solve and write in interval notation for the solution set
\n" ); document.write( "-5 <_ 2x + 1 < 7[isolate the x variable]
\n" ); document.write( "-5-1 <_ 2x + 1-1 < 7-1
\n" ); document.write( "-6 <_ 2x < 6
\n" ); document.write( "-6/2 <_ 2x/2 < 6/2
\n" ); document.write( "-3 <_ x < 3
\n" ); document.write( ".
\n" ); document.write( "[-3, 3)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );