document.write( "Question 827450: three brothers have ages that are consecutive multiples of five, the sum of their ages two years ago was 69. what are their ages now? \n" ); document.write( "
Algebra.Com's Answer #498690 by stanbon(75887)\"\" \"About 
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three brothers have ages that are consecutive multiples of five, the sum of their ages two years ago was 69. what are their ages now?
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\n" ); document.write( "1st: 5x-5
\n" ); document.write( "2nd: 5x
\n" ); document.write( "3rd: 5x+5
\n" ); document.write( "--------
\n" ); document.write( "Equation:
\n" ); document.write( "5x-7 + 5x-2 + 5x+3 = 69
\n" ); document.write( "----
\n" ); document.write( "15x - 6 = 69
\n" ); document.write( "15x = 75
\n" ); document.write( "x = 5
\n" ); document.write( "----
\n" ); document.write( "1st: 5x-5 = 25-5 = 20 yrs
\n" ); document.write( "2nd: 25 yrs
\n" ); document.write( "3rd: 30 yrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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