document.write( "Question 69967: Among U.S. households, 24% have telephone answering machines. If a telemarketing campaign involves 2,500 households, find the probability that more than 650 have answering machines. \r
\n" ); document.write( "\n" ); document.write( "I get .2389
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Algebra.Com's Answer #49867 by stanbon(75887)\"\" \"About 
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I get 0.0096 or less than 1%.
\n" ); document.write( "Converting 650 to a z-score I get:
\n" ); document.write( "z(650)=[650-600]/sqrt(2500*0.24*0.76)=2.34
\n" ); document.write( "which means that 650 is 2.34 standard
\n" ); document.write( "deviations to the right of the mean which
\n" ); document.write( "is 600.
\n" ); document.write( "The probability of the number being greater
\n" ); document.write( "than 650 is very small just as the probability
\n" ); document.write( "of z being greater than 2.34 is very small.
\n" ); document.write( "Hope this helps.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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